Question

please say what is the answer steps to the answer
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Answer 1

Answer:

sin x = $\frac{1}{\sqrt{10} }$

Step-by-step explanation:

Let the side of the square be a , then the base of the triangle = 3a

the altitude will be a .

Then , $hypotenuse^{2} }$ = $altitude^{2}+base^{2}$ [ pythagoras theorem ]

          hypotenuse =$\sqrt{altitude^{2}+base^{2}}$

                               =$\sqrt{(3a)^{2} + a^{2} }$

                               = $\sqrt{9a^{2} + a^{2} }$

                              = $\sqrt{10a^{2} }$

                              = a$\sqrt{10}$

then sin x= $\frac{opposite}{hypotenuse} =\frac{altitude}{hypotenuse} = \frac{a}{a\sqrt{10} } = \frac{1}{\sqrt{10} }$