Question

please see above picture ☝️ please..

in figure angle A=65 degrees,
angle ABC=56 and BO,CO
are the bisectors of angles angle ABC and angle BCA respectively then find angleOCB and angle BOC.

please answer step by step explaination
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and don't give any irrevelent answers please....​

Answer 1

Answer:

By angle sum property

angle A + angleB + angle C = 180

65+56+C=180

121+C=180

C = 180-121

C = 59

BO & CO are bisectors so they divide angle B & C in halves

obc=28

ocb=29.5

angle boc by ASP

28+29.5+O=180

O=180-57.5

O=122.5

Answer 2

Answer:

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