please see the attachment
Attachments:
Answers
Answered by
0
let two vector
a = 4 unit
b = 5 unit
angle α = 60
R = √(a²+b²+2abcosα)
= √(4²+5²+2*4*5*cos60)
= √(16+25+40/2)
= √(61) unit
tanβ = bsinα / (a+bcosα)
= 5*√3/2 / (4+5*1/2)
= 5*√3/2 / (13/2)
tanβ = 5√3/13
β = tan^-1(5√3/13)
a = 4 unit
b = 5 unit
angle α = 60
R = √(a²+b²+2abcosα)
= √(4²+5²+2*4*5*cos60)
= √(16+25+40/2)
= √(61) unit
tanβ = bsinα / (a+bcosα)
= 5*√3/2 / (4+5*1/2)
= 5*√3/2 / (13/2)
tanβ = 5√3/13
β = tan^-1(5√3/13)
Similar questions