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Answer:
700cmsq
Step-by-step explanation:
according to rhombus diagonal bisect each other and diagonals are drawn from vertices in the given case the diagonal was from AC that means they bisect A and C
2A) given that lengths of diagonals is 35 cm
and=40 cm
the area of a rhombus =1/2 x 40 x35
the are of the rhombus =700cmsq
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m) Given : ABCD is a rhombus, i.e.,
AB = BC = CD = DA.
To Prove : ∠DAC = ∠BAC, ∠BCA = ∠DCA
Proof : In ∆ABC and ∆CDA, we have
AB = AD [Sides of a rhombus]
AC = AC [Common]
BC = CD [Sides of a rhombus]
∆ABC ≅ ∆ADC [SSS congruence] So,
∠DAC = ∠BAC
∠BCA = ∠DCA
Hence, diagonal AC bisects ∠A as well as ∠C
n). 1st diagonal = 35 cm
2nd diagonal = 40 cm
Area = 1/2 x d1 x d2
= 1/2 x 35x40
= 700 cm.sq
AB = BC = CD = DA.
To Prove : ∠DAC = ∠BAC, ∠BCA = ∠DCA
Proof : In ∆ABC and ∆CDA, we have
AB = AD [Sides of a rhombus]
AC = AC [Common]
BC = CD [Sides of a rhombus]
∆ABC ≅ ∆ADC [SSS congruence] So,
∠DAC = ∠BAC
∠BCA = ∠DCA
Hence, diagonal AC bisects ∠A as well as ∠C
n). 1st diagonal = 35 cm
2nd diagonal = 40 cm
Area = 1/2 x d1 x d2
= 1/2 x 35x40
= 700 cm.sq
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