Math, asked by 5honey, 8 months ago

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Answered by suryameghan
0

Answer:

700cmsq

Step-by-step explanation:

according to rhombus diagonal bisect each other and diagonals are drawn from vertices in the given case the diagonal was from AC that means they bisect A and C

2A)  given that lengths of diagonals is 35 cm

                       and=40 cm

   the area of a rhombus =1/2 x 40 x35

                 the are of the rhombus =700cmsq

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Answered by koyena3101
0
m) Given : ABCD is a rhombus, i.e.,
AB = BC = CD = DA.
To Prove : ∠DAC = ∠BAC, ∠BCA = ∠DCA

Proof : In ∆ABC and ∆CDA, we have
AB = AD [Sides of a rhombus]
AC = AC [Common]
BC = CD [Sides of a rhombus]
∆ABC ≅ ∆ADC [SSS congruence] So,
∠DAC = ∠BAC
∠BCA = ∠DCA

Hence, diagonal AC bisects ∠A as well as ∠C


n). 1st diagonal = 35 cm
2nd diagonal = 40 cm
Area = 1/2 x d1 x d2
= 1/2 x 35x40
= 700 cm.sq
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