Question

please see the image

Answer 1

Answer:

Given system of equations are

6x - 2y = 3

6x - 2y - 3 = 0 ----(1)

kx - y = 2

kx - y - 2 = 0 --(2)

Compare above equations with

a1x + b1 y + c1 = 0 and

a2 x + b2 y + c2 = 0, we get

a1 = 6, b1 = -2 , c1 = -3 ;

a2 = k, b2 = -1, c2 = -2 ;

Now,

a1/a2 + b1/b2

[Given they have Unique solution ]

6/k (-2 )/( -1)

6/k 2

k/6 1/2

k* 6/2

kz 3

Therefore,

For all real values of k, except k+ 3,