Question

please selve hots 2.First will be marked as brainliest​

Answer 1

Answer:

$= \frac{ {2}^{x - 3} \times {4}^{b - 4} \times {5}^{2} }{ {2}^{x - 4} \times {4}^{b - 5} \times {5} } \\ = \frac{ {2}^{x - 3} \times {2}^{2b - 8} \times 5}{ {2}^{x - 4} \times {2}^{2b - 10} } \\ = \frac{ {2}^{x - 3 + 2b - 8} \times 5}{ {2}^{x - 4 + 2b - 10}} \\ = \frac{ {2}^{x + 2b - 11} \times 5 }{ {2}^{x+2b-14} } \\ = {2}^{x + 2b - 11 - x -2 b + 10} \times 5 \\ = {2}^{ - 1} \times 5 \\ = \frac{5}{2} \\ \\ = \frac{1}{1 + {x}^{a - b} } + \frac{1}{1 + {x}^{b - a} } \\ = \frac{1}{ \frac{ {x}^{b} + {x}^{a} }{ {x}^{b} }} + \frac{1}{ \frac{ {x}^{a} + {x}^{b} }{ {x}^{a} } } \\ = \frac{ {x}^{b} }{ {x}^{b} + {x}^{a} } + \frac{ {x}^{a} }{ {x}^{a} + {x}^{b} } \\ = \frac{{x}^{b} + {x}^{a} }{ {x}^{a} + {x}^{b} } \\ = 1$