Question

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Answer 1

................... Solutions......................

Fill in the blanks

1) Z - 3M = -2xbar

2) non terminating

3)√225 =15 i.e. rational

4) D = b² - 4ac

MCQ

1) option a i.e. 0

product of 2 and 5 gives 10 with 0 as unit digit.

2) option a

(√3 + 2)² = 3 + 4 + 2(√3)(2)

= 7 + 4√3

3) option a

D = 25 = b² - 4ac

(-1)² - (4)(6)(-k) = 25

1 + 24k = 25

24k = 24. so k = 1.

4) sorry for this.

I don't know meaning of C here.

Answer in one word.

1) HCF of 7 and 117 is 1

LCM of 7 and 117 is 7 x 117 = 819

2) D>0 roots are real and distinct.

3) 3M = Z + 2x bar

3M = 36 + 24 = 60

M = 20

4) LCM of 12 and 15 = 2² x 3 x 5 = 60

True or false

1) false

mean of first 10 natural numbers is (10+1)/2 = 11/2

= 5.5 not 6

2) True

x = -3

2x² + 5x + k = 0 => 2(-3)² + 5(-3) + k = 0

=> 18 -15 +k = 0. => k = -3

3)True

4) False

prime factorisation of denominator of the fraction is 5³ which is in form of 5ⁿ so the above ratio is terminating.

hope this will help you