Question

please send answer of this question fast

Answer 1

$\textbf {Hey there, here is the solution.}$

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$P = 2^{240}$

$Q = 3^{144}$

$R = 17^{60}$

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Rewrite each one them in with with power of 60:

$P = (2^4)^{60}$

$Q = (3^{2.4})^{60}$

$R = 17^{60}$

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60 root all the numbers:

$P = \sqrt[60]{(2^4)^{60}} = 2^4 = 16$

$Q = \sqrt[60]{(3^{2.4})^{60}} = 3^{2.4} = 13.96$

$R = \sqrt[60]{17^{60} } = 17$

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Compare and arrange the numbers in ascending orders:

R, P, Q

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Answer: R, P, Q

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⭐$\textbf {Cheers}$⭐