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Question: 5cos^260°+ 4sec^230°- tan^245°/sin^230°+cos^230°
Solution: 5×(1/2)^2 + 4×(2/√3)^2 - (1)^2/(1/2)^2 + (√3/2)^2
= 5/4+16/3-1/1 /1/4+3/4
= 15+64-12/12 / 1+3/4
= 79-12/12 / 4/4
= 67/12
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