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The first 3 digit no. which is multiple of 6 is 102
and last is 996...
Thus,A.P. will be
102,108,114............996.a is first digit and l is last digit
To find Sn=n/2(a+l)
For n,
first no is 102/6=17
last no is 996/6=166
166-17=149 digits in ap
Sn=n/2(a+l)
Sn=149/2*(102+996)
Sn=81801
and last is 996...
Thus,A.P. will be
102,108,114............996.a is first digit and l is last digit
To find Sn=n/2(a+l)
For n,
first no is 102/6=17
last no is 996/6=166
166-17=149 digits in ap
Sn=n/2(a+l)
Sn=149/2*(102+996)
Sn=81801
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