Question

please send full method.

Answer 1

and for z
first we'll find angle DBC
In triangle DBC
26°+26°+angle DBC=180°
angle DBC=128°
so reflex of Angle DBC=360°-128°=232°
so x=26°
y=26°
z=232°

Answer 2

I hope this will help

AngleACB =X ( by property of isosceles triangle)

In∆ABC,
128+2x=180
2x=180-128=52°
X=26°
In∆DBC,
Y=angleACB =x=26°(by property if isosceles triangle)

AngleDAB=180-128°=52°
Y+52+angleDBA=180
AngleDBA=180-26-52
AngleDBA= =102

Z=360°-x-angleDBA
Z=360-26-102
Z=360-128
Z=232°