Question

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Answer 1

Answer:

MATHS

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Asked on December 27, 2019 by

Mukul Cracker

A can do a piece of work in 9 days and B in 18 days. They began the work together but 3 days before the completion of work A leaves. The time taken to complete the work is:

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ANSWER

Work done by A in 1 day =

9

1

Work done by B in 1 day =

18

1

Work done by B in last 3 days =

18

1

×3=

6

1

Remaining work=1−

6

1

=

6

5

Work done by A and B in 1 day =

9

1

+

18

1

=

18

3

=

6

1

Hence no. of days in which A and B worked together is =

6

1

6

5

=5 days

Then total time to complete the work =3+5=8 days.