Math, asked by hsr24, 7 months ago

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Answered by aryan073
1

Answer:

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 {x}^{2}  - 5x  -  6

 {x }^{2}  - 6x + x - 6 = 0

x(x - 6) + 1(x - 6) = 0

(x - 6)(x + 1) = 0

x  = 6 \: and \: x =  - 1

hence proved

Answered by Anonymous
0

HERE IS UR ANSWER DEAR

x²-5x-6 = 0

x²+ (-6)x + 1x -6 = 0

x (x- 6) +1 (x-6 ) = 0

(x-6) ( x+1) = 0

x= 6 ; x= -1

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