Math, asked by hsr24, 9 months ago

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Answered by sai172982
0

Step-by-step explanation:

2x^2+kx-2=0

2(-2)^2-2k-2=0

6-2k=0

k=3

hence the quad eqn is 2x^2+3x-2=0

2x^2+4x-x-2=0

2x(x+2)-1(x+2)

(2x-1)(x+2)

zeroes of quad eqn:1 and -2

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