Question

Please send it is really urgent .

Answer 1

HEY MATE YOUR ANSWER IS HERE....

$\frac{x}{4} + \frac{y}{3 } = - \frac{1}{12} \: \: \: \: be \: eq \: 1$

$\frac{x}{2} - \frac{5y}{4} = \frac{7}{4} \: \: \: be \: \: eq \: \: 2$

NOW LET

in EQUATION 1 MULTIPY BOTH SIDE BY 12

$3x + 4y = - 1 \: \: \: \: \: be \: eq \: 3$

IN EQUATION 2 MULTIPLY BOTH SIDES BY 4

$2x - 5y = 7 \: \: \: \: be \: \: eq \: \: 4$

NOW IN Eq 3 AND Eq 4

★ BY ELEMINATION METHOD ★

EQUATING ( x )

[ SUBTRACTING EQUATION ]

$\: \: \: \: \: 6x + 8y = - 2 \\ \: \: \: \: \: 6x -15y = 21 \\ ( - ) \: \: \: ( + ) \: \: \: \: \: \: ( - ) \\ - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: 23y = - 23y \\ \\ \\ \\ hence \: y \: = - 1$

NOW PUT THE VALUE OF ( Y ) IN Eq 3

$3x + 4y = - 1$

$3x + 4( - 1) = - 1$

$3x - 4 = - 1$

$3x = 3 \\ \\ \\ \\ \\ hence \: x \: = 1$

★ SO (X) = 1 ★

★ AND (Y) = -1 ★

THANKS FOR YOUR QUESTION

HOPE IT HELPS

★ KEEP SMILING ☺️✌️ ★