Question

Please send me a full solution fast as soon as possible and I will mark as BRAINLIEST

Answer 1

let unit's digit be a,
ten's digit be b,
then, number is 100a+10b+0;
according to first condition,
we get,
(100a+10b)-(100b -10a )=180;
so,90a-90b=180
90(a-b)=180;
a-b=180/90;
a-b=2;
according to second condition,
if 100a is halved=50a,
and b and 0 get interchanged,we get,
new no.= 50a+0+b,
so,50a+b;
now,
(100a +10b)-(50a+b)=454;
50a+9b=454....
solve the two equations to get your answer... hope explanation helps you...