Question

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Answer 1

answer with explanation given

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Answer 2

Question :

• What is area of Triangle with Base 2.8 cm and Height 2.6 cm .

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Given : The Base of Triangle is 2.8 cm & The Height of Triangle is 2.6 cm .

Exigency To Find : Area of Triangle.

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❍ Formula for Finding area of Triangle is Given by :

$\dag\:\:\boxed{ \sf{ Area_{(Triangle)} = \bigg( \dfrac{1}{2} \times b \times h \bigg) }}$

Where,

• b is the Base of Triangle and h is the Height of Triangle.

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$:\implies \sf{ Area = \dfrac{1}{2} \times 2.8 \times 2.6 }\\\\ :\implies \sf{ Area = \dfrac{1}{\cancel {2}} \times \cancel {2.8} \times 2.6 }\\\\ :\implies \sf{ Area = 1.4 \times 2.6 }\\\\\underline {\boxed{\pink{ \mathrm {  Area = 3.64\: cm^2}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { Hence ,\:Area \:of\:Triangle \:is\:\bf{36.4\: cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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