Math, asked by KaifRahmani, 1 year ago

Please send me answer of this question

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Answered by Arshpreet111
0
here the series will be a-3d, a-d, a+d, a+3d
here common difference is 2d
so sum = a-3d+a-d+a+d+a+3d=32........... 1
4a=32
a=8
8-3d, 8-d, 8+d, 8+3d
(8-3d) (8+3d)/(8-d) (8+d)=7:15
64+24d-24d-9d^2/64+8d-8d-d^2=7:15
cross multiply
15(64-9d^2)=7(64-d^2)
960-135d^2= 448-7d^2
960-448=d^2(-7+135)
512=d^2(128)
512/128=d^2
√4=d
2=d
so the no. be
8-6=2
8-2=6
8+2=10
8+6=14
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