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Answers
Answer:
Explanation:
1) Question :
The diagonal of square is 10 cm . Find it's area .
Solution :
Given :
Diagonal of square = 10 cm
To find : area of the entire square .
Area of square = d²/2
Procedure :
According to the formula of square
10²/2 = area
100/2 = area
50 cm² = area
Ans = 50cm²
2) calculate the area of equilateral triangle having side 20 cm .
Given : side of triangle = 20cm
Area of triangle = √3/4 × side² .
Also given that √3 = 1.732 .
Procedure :
Area of equilateral triangle = √3 × 20² /4
Area = 1.732 × 400/4
Area = 1.732 × 100 cm²
Area = 173.2cm²
3. Given : base of triangle is 6cm
Both sides are 5cm .
It's also indicated that there is a perpendicular dropped at the base of the triangle which is also the mid point of triangle as it divides the base into half . We know that the perpendicular will be the height of triangle too .
Procedure :
(Calculating the value of the value of height ) .
By Pythagoras theorem we know that
Base² + height² = hypotenuse ²
3² + height² = 5 ²
Height ² = 25 - 9
Height ² = 16
Height = √ 16
Height = 4
Area of the triangle by formula = 1/2 × height × base
Area = 1/2 × 4 × 6
Area = 12cm²
4) find area of scalene triangle having sides 6cm , 8cm and 10cm .
Given : sides as 6cm , 8cm , 10cm
Also given that are of scalene triangle = √s (s-a)(s-b)(s-c)
S = a +b+c/2
Procedure = s = 6+8+10/2
= 24/2 = 12
Area of triangle = √ 12 ( 12-6)(12-8)(12-10)
Area of triangle = √12(6)(4)(2)
Area of triangle = √12×48
Area of triangle = √336
Area of triangle = 18.330 cm²