Question

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Answer 1

Answer:

In △ABC and △PQR

AB=QR

BC=PQ

CA=PR

Thus, △CBA≅△PQR (SSS rule)the figure AB =QR,AC=PQ and BC=PR . Also <A=50°, <B=60°,then find <Q and <P

⇒ Draw a line segment MO of 6cm.

⇒ Take M as a center draw an angle of 60

o

.

⇒ Take point O as a center draw an angle of 105

o

.

⇒ Cut OR at 4.5cm

⇒ Take R point as a center draw an angle of 105

o

.

⇒ The arc of 105

o

angle and the arc of 60

o

angle intersect with each other at E.

⇒ Hence, MORE is a required Quadrilateral.

⇒ Now, by using scale measure the length of side EM

We get, EM=7.5cm

Answer 2

Answer:

Answer:

Step-by-step explanation:

Given that ABI/CD in the figure.

To find the za and zb in the figure.

So,

From the given figure,

triangle ABCD, ZCBD = 71°, ZBCD= 37°

and zBDE = b° is exterior angle.

Then, 2CBD + 2BCD = 2BDE (by using

exterior angle property)

b° = 108

Again from the given figure,

ZBAC =108° and LACD =( a° + 37° )

ZBAC + ZACD =180° (alternate interior

angle)

108° +(a'+37°) = 180°

108° + a' + 37° = 180°

a+ 145° = 180°

a=180° - 145

a°=35

Therefore, a=35° and b°= 108°.