Question

please send me full answers donot send the incorrect answers i will report​

Answer 1

Answer:

12

Step-by-step explanation:

ABC be a triangle having A(0,4);B(0,0);C(3,0)

Using distance formula, we get

AB= √(0−0) 2 +(0−4) 2 = √16 =4

BC= √(3−0) 2 +(0−0) 2=√ 9 =3

CA= √(0−3) 2+(4−0) 2 = √25 =5

Perimeter of △ABC=AB+BC+CA=4+3+5=12

I hope u will understand the answer

Answer 2

Heya!! Here's ur answer

Let A = (0,4) , B =(0,0) and C =(3,0)

Therefore , distance AB= root over (0-0)^2+(0-4)^2

=root over (0)^2+(-4)^2

= root over 0+16

= root over 16

= 4

Again , distance BC = root over (3-0)^2+(0-0)^2

= root over (3)^2+(0)^2

= root over 9

= 3

Also , distance CA = root over (3-0)^2+(0-4)^2

= root over (3)^2+(-4)^2

= root over 9+16

= root over 25

=5

So , perimeter = AB+BC+CA

= 4+3+5

=12

Hence , perimeter of the triangle is 12

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