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Let the three consecutive odd numbers be n,n+2,n+4.
Given that three times, the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one.
3n - 7 = 2(n + 4)
3n - 7 = 2n + 8
3n = 2n + 15
3n - 2n = 15
n = 15.
The 1st number = 15.
2nd number = 15 + 2
= 17.
3rd number = 15 + 4
= 19.
Therefore the numbers are 15,17 and 19.
Hope this helps!
Given that three times, the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one.
3n - 7 = 2(n + 4)
3n - 7 = 2n + 8
3n = 2n + 15
3n - 2n = 15
n = 15.
The 1st number = 15.
2nd number = 15 + 2
= 17.
3rd number = 15 + 4
= 19.
Therefore the numbers are 15,17 and 19.
Hope this helps!
mathematics10:
thanks for helping me
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