Question

please send me full solution as soon as possible and I will mark as BRAINLIEST

Answer 1

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Answer 2

Let the consecutive even numbers be x and x + 2.

Given that the square of greater of two consecutive even numbers exceeds the smaller by 36.

(x + 2)^2 = x^2 + 36

x^2 + 4x + 4 = x^2 + 36

4x + 4 = 36

4x = 36 - 4

4x = 32

x = 32/4

x = 8.


Therefore 1st number = 8.

                  2nd number = x + 2

                                        = 8 + 2

                                        = 10.


Therefore the numbers are 8 and 10.


Verification:

(x + 2)^2 = x^2 + 36

(10)^2 = 8^2 + 36

100 = 64 + 36

100 = 100.


Hope this helps!