Question

please send me it's solution​

Answer 1

Step-by-step explanation:

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Answer 2

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AnsWer:-

$\leadsto \bf{x = 3 \: and \: y = 5}$

Solution:-

${ \sf{let \: \frac{1}{x + y} = p \: and \: \frac{1}{x - y} = q}}$

Now, equation becomes;

${ \tt{16p + 2q = 1 \: \: \: .....(1)}} \\ \\ { \tt{8p - 12q = 7 \: \: \: .....(2)}} \\ \\ { \sf{solving \: these \: equations}}$

and dividing equation (2) by 2

${ \tt{{ \cancel{16p }}+ 2q = 1}} \\ { \tt{{ \cancel{16p }}- 24q = 14}} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:{ \tt{ q = \frac{{ \cancel{14}}}{ \cancel{24} }}} \\ \\ { \bf{q = \frac{</strong><strong>-</strong><strong>1}{2} }}$

putting q= -1/2 into equation (1) and solving we get

${ \tt{16p +{ \cancel{ 2 }}\times \frac{</strong><strong>-</strong><strong>1}{ \cancel{2} } = 1}} \\ \\ { \bf{p = \frac{1}{</strong><strong>8</strong><strong>} }}$

putting these into the above p and q values;

${ \tt{ \frac{1}{x + y} = \frac{1}{</strong><strong>8</strong><strong>} }} \\ \\ \leadsto \:{ \tt{ x + y = </strong><strong>8</strong><strong>}} \: \: \: ...(3) \\ { \bf{and}} \\ { \tt{\frac{1}{x - y} = \frac{</strong><strong>-</strong><strong>1}{2} }} \\ \\ \leadsto \: { \tt{</strong><strong>-</strong><strong>x </strong><strong>+</strong><strong> y = 2}} \: \: \: ...(4)$

Solving equation (3) and (4);

-x+y=2

x+y=8

-2x=-6

x=6/2

x= 3 and y = 5