Math, asked by bharatpatidar451, 1 month ago

please send me maths chapter 3 notes pik​

Answers

Answered by Kippurandthe
0

Step-by-step explanation:

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Exercise 3.1

Ex 3.1 Class 7 Maths Question 1.

Find the range of heights of any ten students of your class.

Solution:

Let us have the heights of 10 students are as follows:

140 cm, 141.5 cm, 138 cm, 150 cm, 161 cm,

138 cm, 140.5 cm, 135.5 cm, 160 cm, 158 cm

Here, minimum height = 135.5 cm

Maximum height =161 cm

∴ Range = Maximum height – Minimum height

= 161 cm — 135.5 cm = 25.5 cm

Hence, the required range = 25.5 cm.

Ex 3.1 Class 7 Maths Question 2.

Organise the following marks in a class assessment in a tabular form.

4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7

(i) Which number is the highest?

(ii) Which number is the lowest?

(iii) What is the range of the data?

(iv) Find the arithmetic mean.

Solution:

Let us form a frequency distribution table:

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling 1

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling 2

(i) 9 is the highest marks.

(ii) 1 is the lowest marks.

(iii) Range = Max. marks – Min. marks

= 9 – 1 = 8

(iv) Arithmetic mean = ΣfixiΣfi=10020=5

Ex 3.1 Class 7 Maths Question 3.

Find the mean of first five whole numbers.

Solution:

First 5 whole numbers are 0, 1, 2, 3, 4

∴ Mean =0+1+2+3+45=105=2

Hence, the required mean = 2.

Ex 3.1 Class 7 Maths Question 4.

A cricketer scores the following runs in eight innings:

58, 76, 40, 35, 46, 45, 0, 100

Find the mean score.

Solution:

Following are the scores of the runs in eight innings:

58, 76, 40, 35, 46, 45, 0, 100

∴ Mean = = Sum of all runs Number of innings

=58+76+40+35+46+45+0+1008=4008=50

Hence, the required mean = 50.

Similar questions