Question

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Answer 1

Explanation:

1 minute= 60 seconds frequency is no of oscillations in 1 second frequency= total oscillations/given time in seconds F= 40/60=0.66 Hertz time period= 1/frequency, time period=1/0.66=1.51 second

Answer 2

Question:

A simple pendulum completes40 oscillations in one minute. Find its

(a) frequency,

(b) time period

Solution:

Given :

No of oscillations, N 40

time,t= 1 min = 60 sec

To be found :

a) frequency

b) time period

Solution :

1) We have to find the frequency

We know that Frequency(n) is the number of vibrations (no of complete wavelength) completed by the particle in one second.

$\green{\boxed{\rm{Frequency=\dfrac{Number\ of\ Vibrations}{Time} }}}$

$\sf=\dfrac{N}{t}$

$\sf=\dfrac{40}{60}$

$\sf=\dfrac{2}{3}$

$\sf=0.667Hz$

Thus, Frequency is 0.667 Hz

$\rule{200}2$

2) We have to find the time period.

The Time period is defined as :

Time is taken by the wave to travel a distance equal to 1 wavelength.

${\purple{\boxed{\large{\bold{Time\: Period=\frac{1}{Frequency}}}}}}$

$\sf=\dfrac{1}{n}$

$\sf=\dfrac{3}{2}$

$\sf=1.5sec$

Thus, the time period is 1.5 sec.

$\rule{200}2$

More about topic

1) SI unit of frequency us Hertz (Hz)

2) The relation  between wavelength and frequency, the wavelength is :

$\sf\:v=n\lambda$