Question

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Answer 1

This is your answer

Answer:4

Answer 2

Answer:

$first \: solve \: bracket \\ {9}^{ - 2} \div ( {6}^{ - 2} \times {3}^{ - 2} ) \\ {9}^{ - 2} \div ( { \frac{1}{6} }^{2} \times { \frac{1}{3} }^{2} ) \\ {9}^{ - 2} \div { \frac{1}{18} }^{2} \\ {9}^{ - 2} \div {18}^{ - 2} \\ = 4$

Step-by-step explanation:

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