please send me proof by solving with ASA congruency rule
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mandeep4734:
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proof: In ∆ABC & ∆XYZ
angleB = angle Y
BC = YZ
angle C = angle Z
∆ABC is congruent to ∆ XYZ by ASA criteria
u will understand this, hope it will help u (☆^ー^☆)
best of luck
angleB = angle Y
BC = YZ
angle C = angle Z
∆ABC is congruent to ∆ XYZ by ASA criteria
u will understand this, hope it will help u (☆^ー^☆)
best of luck
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Hello dear Good morning....
Your answer is in down...
ASA congruency rule.let us prove this!!
CaseI=AB=PQ.
In Traingle S ABC and pqr we have-
AB=PQ[By assumption]
<B=<Q[given]
BC=OR[given]
then The two triangles ABC and pqr are congruent I.e.Triangle ABC that is not equal to Traingle PQR[By SAS congruence rule]>
Thanks!!
Your answer is in down...
ASA congruency rule.let us prove this!!
CaseI=AB=PQ.
In Traingle S ABC and pqr we have-
AB=PQ[By assumption]
<B=<Q[given]
BC=OR[given]
then The two triangles ABC and pqr are congruent I.e.Triangle ABC that is not equal to Traingle PQR[By SAS congruence rule]>
Thanks!!
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