Question

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Answer 1

Initial velocity of the stone ,u=20 m/s

final velocity of the stone,v=0

Distance covered by the stone, s=50 m

Explanation:

We know the third equation of the motion

v²=u²+2as

Substituting the known values in the above equation we get,

0² = (20)²+2(a)(50)

-400 = 100a

a = -400/100 = -4m/s² (retardation)

We know that

F = m×a

Substituting above obtained value of a=-4 in F= m x awe get,

F = 1×(-4) = -4N

(Here the negative sign indicates the opposing force which is Friction)