Math, asked by dk6663862, 6 months ago

please send me right answer with full explanation please answer fast​

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Answered by anshikaverma29
9

\text{Given : Lines AB , CD and EF intersect at O.}\\\\\text{To find : $\angle AOC$ and $\angle COF $.}\\\\\text{$\rightarrow$ As lines CD and AB intersect at O so their opposite angles will be equal.}\\\\\text{$\implies \angle$AOC = $\angle$BOD }\\\\\therefore\underline{\mathsf{\angle AOC = 35^{\circ}$ }}\\\\\text{Now, $\angle EOA,\angle AOC,\angle COF$ all lie on a same straight line . }\\\\\text{Hence , their sum should me 180$^{\circ}$.}\\\\\text{$\angle EOA+\angle AOC+\angle COF = 180^{\circ}$}\\\\\\

\\\\\text{$40+35+\angle COF^{\circ}=180$}\\\\ \text{75+ $\angle COF^{\circ}=180$}\\\\\text{$\angle COF^{\circ}$ = 180 - 75}\\\\ \therefore\underline{\mathsf{\angle COF = 105^{\circ}}}

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