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Explanation:
a=0.5m/s
u=90km/h=(90*5/18)m/s=25m/s
v=0(The train is brought to rest)
so, as we know,
v^2=u^2+2as(third equation of motion)
or, 0^2=25^2 - 2*0.5.s(as the body retards,u>v)
or, s=625m(answer)
The train will go 625m before it comes to rest.
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