Please send me solution of this problem with explanation
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Angle <BOC is 90
because as it is given that oa ob oc are following Pythagoras theorem and oa will be the hypotenuse we can easily extrapolate it if we can redraw the triangle with sides of OA OB OC
because as it is given that oa ob oc are following Pythagoras theorem and oa will be the hypotenuse we can easily extrapolate it if we can redraw the triangle with sides of OA OB OC
Saurabhsingh12345:
it is not a correct answer because on constructing triangle of sides oa ob oc the sides ob and oc may move from their original position
Answered by
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hey friend your answer is here
in an equilateral triangle centroid, orthocenter, circumcenter & incenter lies at one point .Therefore the angle AOB ,BOC & AOC are congruent
AOB = BOC = AOC
AOB+BOC+AOC = 360°
AOB+AOB+AOB =360°
3AOB =360°
AOB =360°/3
angle AOB =120°
therefore , angle BOC =120°
please make me a brainlist answer for the question
in an equilateral triangle centroid, orthocenter, circumcenter & incenter lies at one point .Therefore the angle AOB ,BOC & AOC are congruent
AOB = BOC = AOC
AOB+BOC+AOC = 360°
AOB+AOB+AOB =360°
3AOB =360°
AOB =360°/3
angle AOB =120°
therefore , angle BOC =120°
please make me a brainlist answer for the question
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