Question

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Answer 1

Answer:

★ CHANGE IN WAVELENGTH

[ ∆ LAMBDA ] = 4300 × 10-¹² m

Explanation:

★ COMPTON EFFECT EQUATION ★

★ Given ;

» Rest Mass of Photon ( Mⁿ ) = 9.1 × 10-³¹ Kg

» Planck's Constant ( h ) = 6.6 × 10-³⁴ J-S

» Speed of Light ( C ) = 3 × 10^8 m / s

» Scattering Angle ( ∅ ) = 135°

★ CHANGE IN WAVELENGTH OF X - RAYS ( ∆ LAMBDA ) = ???

______ [ BY USING FORMULA ] _____

$[ lambda \: = \: \frac{Planck's \:constant \: ( \: h \: )}{Rest \: Mass \: ( \: {M}^{n} \: ) \: \times \: speed \: of \: light \: ( \: C \: )} \times \: ( \: 1 \: - \: \cos( \alpha ) ) ]$

★ ∆ Lambda = [ h / Mⁿ × C ] × [1- Cos ∅ ]

» ∆ Lambda = [ 6.6 × 10-³⁴ / 9.1 × 10-³¹ × 3 × 10^8 ] × [ 1 - Cos ∅ ]

= [ 6.6 × 10-³⁴ / 9.1 × 3 × 10-²³ ] × [ 1 - Cos ∅ ]

= [ 6.6 × 10-³⁴ / 27.3 × 10-²³ ] × [ 1 - Cos∅ ]

= [ 1 × 10-³⁴ / 4.1 × 10-²³ ] × [ 1 - Cos ∅ ]

= [ 0.25 × 10-¹¹ ] × [ 1 - Cos ∅ ]

= [ 2.5 × 10-¹² ] × [ 1 - Cos 135° ]

= [ 2.5 × 10-¹² ] × [ 1 - ( - 1 / √2 )

= [ 2.5 × 10-¹² ] × [ √2 + 1 / √2 ]

= [ 2.5 × 10-¹² ] × [ 1.71 ]

★ ∆ LAMBDA = 4.3 Pico metre

----------------------- [ OR ] ----------------------

★ ∆ LAMBDA = 4300 Nano metre

_______________________________________

ANSWER :- CHANGE IN WAVELENGTH OF X - RAYS HAVING SCATTERING ANGLE IS ;

[ ∆ LAMBDA = 4.3 × 10-¹² m ]

Answer 2

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