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Answer 1

Question:-

$\tt{If \: x^{y} + {y}^{x} = {a}^{b} \: then \: prove \: that } \\ \tt{\frac{dy}{dx}= \left[ \frac{ {yx}^{y - 1} + {y}^{x} log \: y}{ {x}^{y} log \: x + {xy}^{x - 1} } \right]} \\ \\ </u></p><p><u>[tex] \tt{If \: x^{y} + {y}^{x} = {a}^{b} \: then \: prove \: that } \\ \tt{\frac{dy}{dx}= \left[ \frac{ {yx}^{y - 1} + {y}^{x} log \: y}{ {x}^{y} log \: x + {xy}^{x - 1} } \right]}$

Answer:-

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