Math, asked by chandu987, 10 months ago

Please send solution as much as possible ​

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Answered by arulmary181
1

Step-by-step explanation:

nPr=720

n!/(n-r)!=720___(1)

nCr=120

n!/(n-r)!r!=120____(2)

(1)/(2)==>r!=720/120

r!=6

r=6

put r=6 in (1)

n!/(n-6)!=720

n(n-1)(n-2)(n-3)(n-4)(n-5)(n-6)!/(n-6)!=720

n(n-1)(n-2)(n-3)(n-4)(n-5)=720

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