Math, asked by AnshrajDwivedi18, 11 months ago

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Answers

Answered by Abhishek474241
1

Given

some problems related to factorisation

Solution

  1. Simplify (a+b+c)² + (a-b-c)²

Break the terms

=>+++2ab+2bc+2ac+a²+b²+c²-2ab+2bc

-2ac

=>2a²+2b²+2c²+4bc

2.

(4x+2y)³-(4x-2y)³

Breaking it into a³-b³

a³-b³ = (a-b) (a²+b²+2ab)

=>(4x+2y)³-(4x-2y)³ =(4x+2y-4x+2y) (16x²+4y²+16xy+16x²+4y²-16xy+(16x²-4y²)

=>(4y) (48x²+4y²)

3.

similarly you can break question 3

  • and spilt terms
  • like (a+b)³ = (a+b)(a+b)(a+b)

4.

Spilting the middle term

x²+7x-44

x²+11x-4x-44

=>X(X+11)-4(X+11)

=>(x-4) (X+11)

5)

similar questions

easily break

6.)

27a³+125b³

=>(3a)³+(5b)³

=>(3a+5b) (9a²+25b²-15ab)

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