Question

Please send step by step solution!!!

Answer 1

Answer:

$x =\sqrt[3]{9} = {3}^{2} \times 9 = 27.$

$y = \sqrt[4]{11} = {4}^{2} \times 11 = 176.$

$z = \sqrt[6]{17} = {6}^{2} \times17 = 612.$

Therefore,

$z > y > x.$

That is, Option C.

Answer 2

Answer:

Step-by-step explanation: