Question

please send the ans please​

Answer 1

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✰Answer✰

♦️GiveN

• Side of Rhombus = 6 cm
• Altitude of Rhombus= 4 cm
• One of the diagonal = 8 cm

♦️To FinD

• Find the other diagonal?

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✰Solution✰

☛Since rhombus is a type of parallogram,

$\large{ \boxed{ \green{ \tt{area \: of \: rhombus = base \times heighe}}}}$

Putting the Given values of Base (side)= 6 cm

And, the value of Altitude(Height) = 4 cm

☛Area of rhombus,

$\large{ \tt{ = base \times height}} \\ \\ \large{ \tt{ = 6 \: cm \times 4 \: cm}} \\ \\ \large{ = \boxed{ \tt{24 \: {cm}^{2} }}}$

♦️Area of Rhombus = 24 cm^2

Now, Finding the length of Diagonal:

We have, one of the diagonal = 8 cm

Let another diagonal be d2,

$\large{ \boxed{ \green{ \tt{area \: of \: rhombus = \frac{1}{2} \times (product \: of \: diagonals)}}}}$

☛By using this,

$\large{ \tt{ \rightarrow \: area \: of \: rhombus = \frac{1}{ \cancel{2}} \times \cancel{8 } \: \: 4 \: \times d2}} \\ \\ \large{ \sf{ \rightarrow \: 24 \: {cm}^{2} = 4 \: cm \times d2}} \\ \\ \large{ \tt{ \rightarrow \: \boxed{ \purple { \tt{d2 = 6cm}}}}}$

☛Length of other daigonal = 6 cm

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↪Refer the attachment for diagram.

Answer 2

Question :

Find the area of rhombus whose sides is 6 cm and whose altitude is 4 cm. If one of its diagonal is 8 cm long, Find the length of other diagonal.

Given :

• Sides of rhombus is 6 Cm.
• And altitude is 4 Cm.
• One Its diagonals is 8 Cm.

To Find :

• Length of other diagonal.
• Area of rhombus.

Solution :

Condition,

• When we added area both triangle i.e, triangle BCD and triangle DAB we get Area of Rhombus.
• CM altitude of rhombus. ( 90° )

$\tt \dagger \: \: \: \: \: Area \: of \: \triangle BCD +Area \: of \: \triangle DAB = Area \: of \: Rhombus.$

$\tt \longmapsto Area_R = 2 \times \dfrac{1}{2} \times base \times height$

$\tt \longmapsto Area_R = \cancel{2} \times \dfrac{1}{ \cancel2} \times 6 \times4.$

$\tt \longmapsto Area_R = 6 \times 4.$

$\tt\longmapsto Area_R = 24 \: c {m}^{2} .$

$\rule{90}1$

Now,

Let,

• D1 ( one diagonal )
• D2 ( Other diagonal )

$\tt \dagger \: \: \: \: \: Area \: of \: Rhombus = \dfrac{1}{2} \times D_1 \times D_2.$

$\tt \longmapsto Area_R = \dfrac{1}{\cancel2} \times \cancel8 \times D_2.$

$\tt \longmapsto 24= 4 \times D_2.$

$\tt\longmapsto \dfrac{\cancel{24}}{\cancel4} = D_2.$

$\tt \longmapsto D_2= 6 \: cm.$

Therefore, the area of Rhombus is 24 cm² and its other diagonal is 6 Cm.