Question

please send the answer immediately I have urgently needed this question​

Answer 1

$3 (\frac{3x - 1}{2x + 3} ) - 2 (\frac{2x + 3}{3x - 1} ) = 5 \\ \frac{9x - 3}{2x + 3} - \frac{4x - 6}{3x - 1} = 5 \\ \frac{(9x - 3)(3x - 1) - (4x - 6)(2x + 3)}{6x {}^{2} - 2x + 9x - 3 } = 5 \\ \frac{27x {}^{2} - 18x + 3 - (8x {}^{2} - 18)}{6x { }^{2} + 7x - 3} = 5 \\ 19x {}^{2} - 18x - 15 = 30x {}^{2} + 35x - 15 \\ 19x {}^{2} - 30x {}^{2} - 18x - 35x - 15 + 15 = 0 \\ - 11x {}^{2} - 48x = 0 \\ 11x {}^{2} + 48x = 0 \\ x(11x + 48) = 0$

Either x = 0

or

11x + 48 = 0

11x = –48

x = – 48/11

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