Please send the answer in structured way , how you solved it ?
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M is the image of L in the water so that BL=BM.p is a point at height h above level of water at which the angle of elevation of L is α and the angle of depression of M is β. We have to find BL=x, say.
Let AB=PR=y
LR=ytanα, MR=ytanβ
∴
x−h
x+h
=
ytanα
ytanβ
=
tanα
tanβ
.
Apply comp. and divi.
2h
2x
=
tanβ−tanα
tanβ+tanα
x=h
tanβ−tanα
tanβ+tanα
...(1)
Another form. If we divide above and below of (1) by tanαtanβ, then
x=h
cotβ−cotα
cotβ+cotα
If we change in terms of sin and cos, then from (1)
x=h
sin(β−α)
sin(β−α)
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