Math, asked by Souravsamal, 11 days ago

please send the answer it my test​

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Answers

Answered by gourabmanjunath
0

Answer:

1. 13

2.6

3.-1

Step-by-step explanation:

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Answered by Anonymous
233

 \footnotesize \sf \purple{Solution:-}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \footnotesize \sf{1) \: x +12 = 25}

 \footnotesize \sf{\: x = 25 - 12}

    \purple \bullet \: \boxed{\boxed{\footnotesize \sf{\: x = 13}}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \footnotesize \sf{2) \: Additive \:  inverse \:  of  \: -6 \:  is  \: 6}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \footnotesize \sf{3) \:  \frac{ - \:  4}{19}   \: \times  \:  \:  \:  \:  =  \frac{4}{19} }

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \footnotesize \sf \purple{Let \:  missing  \: number \:  be \:  x}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \footnotesize \sf{x  =  \frac{4}{19} \times  \frac{19}{ -  \: 4}  }

 \footnotesize \sf{x  = \cancel  \frac{ 4}{19} \times  \cancel \frac{19}{ -  \: 4}  }

    \purple \bullet \: \boxed{\boxed{\footnotesize \sf{\: x =  - 1}}}

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