Question

please send the answer quickly​

Answer 1

Answer:

As we know that altitude to the side of equilateral triangle bisect it.

Therefore BD=a/2

Now, using Pythagoras theorem

AD Sq. +BD Sq. =AB Sq.

AD sq=a Sq. - a Sq. /4

$ad {}^{2} = (4a {}^{2} - a {}^{2} ) \div 4 \\ \\ ad {}^{2} = 3a {}^{2} \div 4 \\ \\ ad = \sqrt{3}a \div 2$

Ans =root3 /2

Mark as brainliest please

Answer 2

Hi raj

I hope this helps u