Question

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Answer 1

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i)Ester.

ii)The odour will be sweet-smelling.

iii)Esterification.

iv)CH3COOH + C2H5OH------CH3COOC2H5+H2O

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Answer 2

Answer:

Given:

Glacial acetic acid and ethanol are mixed . A few drops of sulphuric acid is added and the test run is heater on water bath

To find:

The above questions.

Explanation:

1. The compound formed is an ester.

The name is

Ethyl-ethanoate.

As a by-product, Water is also produced.

2. Esters are sweet smelling compunds. Hence Ethyl-ethanoate is odoriferous and has sweet (good) smell.

3. This type of Reactions are called

ESTERIFICATION REACTION.

4. The Equation for the above reaction

$CH3COOH + C2H5OH => CH3COOC2H5 \\ + H20$

Additional information:

1. Sulphuric acid acts as a catalyst.

2. The test tubes are heated in a water bath to prevent flame formation.

3. In this reaction, the acid acts as OH- donor and the alcohol acts as H+ donor.