Question

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Answer 1

Answer:

Step-by-step explanation:

Q 9

ABCD is a cyclic quadrilateral ,so opposite angles are supplementary

So ∠ ABC=180-∠ADC

=180-120=60

Now ∠ ABC + ∠CBE=180 ( adjacent angles)

60+x=180

x=180-60

X=120°

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Q10 OA=OB=r

∠ OBA=∠OAB=40°

In the Δ OAB

∠OAB+∠OBA+∠AOB=180

40+40+∠AOB=180

∠AOB =180-80=100

Now

∠AOB =2*∠ACB

100=2*∠ACB

∠ACB=100/2=50°

Answer 2

☺ａｎｓｗｅｒ:

upper answer is right..

sorry