please show complete method. will be great help
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answer for the given problem is given
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ANGLE DAB= ANGLE EAC ( VERTICALLY OPPOSITE ANGLES)
AB=AC (GIVEN)
Angle BDA= ANGLE EAC (ALTERNATE ANGLES)
THIS PROVES THAT ∆DAB = ∆EAC (AAS)
BD= CE (CONGRUENT PARTS OF CONGRUENT TRIANGLE ARE EQUAL)
AD=AE ((CONGRUENT PARTS OF CONGRUENT TRIANGLE ARE EQUAL)
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