please show how. would appreciate the help
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dragomegaman:
solved it myself. no need to answer it
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RHS
= ( x - 1 ) ( x + 2 )
= x ( x + 2 ) - 1 ( x + 2 )
= x² + 2 x - x - 2
= x² + x - 2
= LHS
Hence proved
= ( x - 1 ) ( x + 2 )
= x ( x + 2 ) - 1 ( x + 2 )
= x² + 2 x - x - 2
= x² + x - 2
= LHS
Hence proved
your answer does not help at all. I wanted to know how to arrive at RHS and not LHS. anyway i found it myself.
Reverse woks the same way
Answered by
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Hey there!!
Down here ⏬
☆ x^2 + x -2 = (x-1) (x+2)
☆ Equation in the form of identity (x+a) (x+b) = x^2 + (a+b) x + ab
☆ Where, x = x ; a = -1 ; b = 2
☆ (x-1) (x+2) = x^2 + (-1+2) × x + (-1×2)
= x^2 + 1 × x + (-2)
= x^2 + x-2
☆ Hence, the desired result
LHS = RHS
x^2 +x-2 = (x-1) (x+2)
Hope it helps. ♥
Down here ⏬
☆ x^2 + x -2 = (x-1) (x+2)
☆ Equation in the form of identity (x+a) (x+b) = x^2 + (a+b) x + ab
☆ Where, x = x ; a = -1 ; b = 2
☆ (x-1) (x+2) = x^2 + (-1+2) × x + (-1×2)
= x^2 + 1 × x + (-2)
= x^2 + x-2
☆ Hence, the desired result
LHS = RHS
x^2 +x-2 = (x-1) (x+2)
Hope it helps. ♥
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