Math, asked by Arjundas111, 1 year ago

please show me the sum step by step

Attachments:

Answers

Answered by NavyaArohi
3

 \sqrt{20}  =  \sqrt{(5 \times 4)}  =  \sqrt{5}  \times  \sqrt{4}  = 2 \sqrt{5}  \\  \sqrt{40}  =  \sqrt{(10 \times 4)}  =  \sqrt{10}  \times  \sqrt{4}  = 2 \sqrt{10}  \\  \sqrt{80}  =  \sqrt{(16 \times 5)}  =  \sqrt{16}  \times  \sqrt{5}  = 4 \sqrt{5}  \\in \: denominator \: of \: que \\  \sqrt{10}  + 2 \sqrt{10}  =  \sqrt{10} (1 + 2) = 3 \sqrt{10}  \\ 2 \sqrt{5}  -  \sqrt{5}  - 4 \sqrt{5}  =  \sqrt{5} (2 - 1 - 4) =  - 3 \sqrt{5}  \\ now \: in \: equation \:  \\ 15 \div (3 \sqrt{10}  - 3 \sqrt{5} ) = 5 \times 3 \div 3( \sqrt{10} -  \sqrt{5}  ) = 5 \div ( \sqrt{10}  -  \sqrt{5} )

Arjundas111: thank you
Arjundas111: can you please explain it to me briefly
Arjundas111: what's after 5/((root over10)-(root over5))?
NavyaArohi: put values of root over 10 and 5 in the equation
Arjundas111: but the answer is not coming
Arjundas111: the answer,as ststed in the book,is5.398
Arjundas111: but my answer,what is coming from the sum,is5.398
Arjundas111: I mean 5.399
NavyaArohi: ans is 5.399 its ok. procedure is correct and value is already given in que.
Similar questions