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Step-by-step explanation:
Given that,
In a ΔABC , ∠A = 3x, ∠B = 5x and ∠C = 8x + 4°.
We know that, the sum of the three angles of a triangle is 180°.
∴ ∠A + ∠B + ∠C = 180°
⇒ 3x + 5x + 8x + 4° = 180°
⇒ 16x + 4° = 180°
⇒ 16x = 180°- 4°
⇒ 16x = 176°
⇒ x = 176° / 16
⇒ x = 11°
∴ The three angles of a ΔABC are
3x = 3 × 11° = 33°,
5x = 5 × 11° = 55° , and
8x + 4°= 8 × 11° + 4° = 88° + 4° = 92° is the answer.
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