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Answer:
x = 30°
Step-by-step explanation:
Δ JKL
If JK ≅ KL , then ∠J ≅ ∠L ⇒ 2x - y = x + 2y ⇒ x - 3y = 0 .... (1)
m∠J + m∠K + m∠L = 180° ⇒ (2x - y) + (2x + 2y) + (x + 2y) = 180° ⇒ 5x + 3y = 180° .... (2)
(1) + (2)
6x = 180° ⇒ x = 30°
y = 10°
m∠J = m∠L = 50° and m∠K = 80°
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