Question

Please show your work

Answer 1

Answer:

x = 30°

Step-by-step explanation:

Δ JKL

If JK ≅ KL , then ∠J ≅ ∠L ⇒ 2x - y = x + 2y ⇒ x - 3y = 0 .... (1)

m∠J + m∠K + m∠L = 180° ⇒ (2x - y) + (2x + 2y) + (x + 2y) = 180° ⇒ 5x + 3y = 180° .... (2)

$\left \{ {{x-3y=0} \atop {5x+3y=180}} \right.$

(1) + (2)

6x = 180° ⇒ x = 30°

y = 10°

m∠J = m∠L = 50° and m∠K = 80°