Math, asked by sj273051, 4 months ago

please slove and give fast​

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Answers

Answered by senboni123456
0

Step-by-step explanation:

Ww have,

 \sqrt{ \frac{x}{x - 3} }  +  \sqrt{ \frac{x - 3}{x} }  =  \frac{5}{2}  \\

let \:  \: y =  \sqrt{ \frac{x}{x - 3} } \\

 =  > y +  \frac{1}{y}  =  \frac{5}{2}  \\

 =  >  {y}^{2}  + 1 =  \frac{5y}{2} \\

 =  > 2 {y}^{2}  - 5y + 2 = 0

 =  > 2 {y}^{2}  - 4y - y + 2 = 0

 =  > 2y(y - 2) - 1(y - 2) = 0

 =  > (y - 2)(2y - 1) = 0

 =  > y = 2 \:  \: or \:  \: y =  \frac{1}{2} \\

 =  >   \sqrt{ \frac{x}{x - 3} }  = 2 \:  \: or \:  \:   \sqrt{ \frac{x}{x - 3} }  =  \frac{1}{2}  \\

 =  >  \frac{x}{x - 3}  = 4 \:  \: or \:  \:  \frac{x}{x - 3}  =  \frac{1}{4}  \\

 =  > x = 4x - 12 \:  \: or \:  \: 4x = x - 3

 =  > 3x = 12 \:  \: or \:  \: 3x =  - 3

 =  > x = 4 \:  \: or \:  \: x =  - 1

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